A solid weighs 80g in air, 68g in water and 60g in oil. Calculate the relative density of oil and solid.

$D=\frac{{W}_{a}}{{W}_{a}-{W}_{w}}$

On substituting the values in the above equation we get,

$D=\frac{80g}{80g-68g}\phantom{\rule{0ex}{0ex}}D=\frac{80g}{12g}\phantom{\rule{0ex}{0ex}}D=6.67$

So, as the relative density of solid is $D=6.67$.

Similarly, the relative density of oil can be calculated as,

$D\text{'}=\frac{lossinweightinoil}{lossinweightinwater}\phantom{\rule{0ex}{0ex}}D\text{'}=\frac{{W}_{a}-{W}_{oil}}{{W}_{a}-{W}_{water}}$

On substituting the values we get,

$D\text{'}=\frac{80g-60g}{80g-68g}\phantom{\rule{0ex}{0ex}}D\text{'}=\frac{20g}{12g}\phantom{\rule{0ex}{0ex}}D\text{'}=1.67$

Thus, the relative density of oil is $D\text{'}=1.67$

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